Calculus II - Review Worksheet  --  If you find any mistakes in the solutions, email me at abigailh@elmhurst.edu

  1. Sketch the following functions and state the domain and range of each.
    2.


     

     

    a.                                                                              b. 

                        
     

        Domain is                                                                        Domain is
        Range is                                                                              Range is
     
     
     
     

    c. 

                Domain is
                Range is [- 1, 1]
     
     

  2. Find the line tangent to each function at the given x
    3. -value.
    1. at x = 2

      2.  

       

      So, the slope of the tangent line is - 12.
      Now, a point on the line is (2, - (2)3) = (2,- 8).

      So, the equation of the line is , which simplifies to .
       

    2. at x = p / 4

      3.  

      So, the slope of the tangent line is .

      Now, a point on the line is (p / 4, cos(p / 4)) = (p / 4,).

      So, the equation of the line is , which simplifies to .
       

    3. at x = 1

So, the slope of the tangent line is 0. This means that the tangent line is horizontal. Since it goes through the point (1, 81), the equation of the tangent line is y = 81.
 
  1. Evaluate the following integrals.
    2.


     

     

    a.                                                                              b. 

                                                         
     

    c.                                                              d. 
     

                                                                       
                
     

    e.                                                              f. 

                              
     
     

  2. Express the area of the shaded region on the right as:
    3.

  1. a  limit of a sum.
    2.


     

     

                    
     
     

  2. a definite integral.
    3.

        

 

 5. Consider the equation  y = x2 - 3.

a. If x = 1, what is y?

y = 12 - 3 = -2

b. Is y a function of x?  Why or why not?

Yes, for each x value, there is only one corresponding y value.

c. If y = 1, what is x?

1 = x2 - 3
4 = x2
x = 2 or -2

d. Is x a function of y?  Why or why not?

No, for some y values there are more than one corresponding x values.


 
 
 
  1. a. If 
    2.
, find 

b. Find .