This region is the half-plane that is above (and not including)
the plane z=4,which is the plane parallel to and 4 units above
the xy-plane
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This is a circular cylinder with radius 3 units. It wraps
around
the x-axis and extends infinitely.
This is the same as asking how far out the point is in
the positive or negative x-direction. So the distance
is the absolute value of the x-coordinate, in this case
that is 2 units.
Another way to complete this problem is to realize
that the point on the yz-plane that is closest to the
given point is (0,3,4). you can then compute the
distance between the two points, which is 2 units.
The point on the z-axis that is closest to the given point
is (0,0,4). We use the distance formula:
d= sqrt{(-2-0)^{2}+(3-0)^{2}+(4-4)^{2}}= sqrt{13}units.