Another way to do this problem is to draw the
appropriate branch of the probability tree, which would look like:
.
So the probability is (1/2)·(1/2)·(1/2) = 1/8
P(3 then 5) + P(5 then 3) = (1/13)·(1/13) + (1/13)·(1/13) = 1/169 + 1/169 = 2/169.

A 6-sided die is rolled. If the number that appears is odd, then
you receive $2. If a 2 or 4 appear, then you receive $3. If a 6 appears,
then you have to give them $6.
If they wish to charge you $1.50 each time you play this game, is this a good deal for you?
| Die roll | Result | Probability |
| 1, 3, 5 | $2.00 | 1/2 |
| 2, 4 | $3.00 | 1/3 |
| 6 | –$6.00 | 1/6 |
|
1
|
7 7 8 9 |
|
2
|
2 5 6 6 6 7 |
|
3
|
1 9 |
|
4
|
2 4 4 5 8 9 9 |
|
5
|
1 1 1 2 2 3 3 |
|
6
|
5 6 4 5 5 7 |
|
7
|
|
|
8
|
4 |
